12^(5x)+^2=19

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Solution for 12^(5x)+^2=19 equation: 



12^(5x)+^2=19

We move all terms to the left:

12^(5x)+^2-(19)=0

determiningTheFunctionDomain
12^5x-19+^2=0

We add all the numbers together, and all the variables

12^5x=0

x=0/1

x=0

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